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Ion Electron Method

For the react...

Question

For the reaction between $K M n O_{4}$ and $H_{2} O_{2}$ , the number of electrons transferred per mole of $H_{2} O_{2}$ is:

One

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Two

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Three

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Four

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Solution

The correct option is B Two
$3 H_{2} O_{2} + 2 K M n O_{4} - > 3 O_{2} + 2 M n O_{2} + 2 K O H + 2 H_{2} O$
$Number of electron transfer per mole of$ $H_{2} O_{2}$ $is 2.$

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K M n O_{4}

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H_{2} O_{2}

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H_{2} O_{2} + K M n O_{4} + H_{2} S O_{4} \to M n S O_{4} + H_{2} O + O_{2} + K_{2} S O_{4}

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