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Oxidation Number Method

For the react...

Question

For the reaction between $K M n O_{4}$ and $H_{2} O_{2}$ , the number of electrons transferred per mol of $H_{2} O_{2}$ is?

One

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Two

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Three

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Four

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Solution

The correct option is A Two
The half reactions are
$2 M n {O_{4}}^{-} + 16 H^{+} + 10 e^{-} \to 2 {M n}^{+ 2} + 8 H_{2}$
$5 H_{2} O_{2} \to 5 O_{2} + 10 H^{+} + 10 e^{+}$

The number of electron transferred per mole of hydrogen peroxide = 10/5 = 2 Hence, option B is the correct answer.

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