Question

For the reaction between $KMn{O}_4$ and $H_2{O}_2$, the number of electrons transferred per mole of $H_2{O}_2$ is:

• A. One
• B. Two
• C. Three
• D. Four

Answer 1

The correct option is B Two

The half reactions are:
$2Mn{O}_4^{-}+16H^{+}+10e^{-}\to 2M{n}^{2+}+8H_2$
$5H_2{O}_2\to 5O_2+10H^{+}+10e^{-}$
The number of electron transferred per mole of hydrogen peroxide $=10/5=2$.
Hence, option (b) is the correct answer.