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Assigning Oxidation Numbers

For the react...

Question

For the reaction ${B r}_{2} + 2 N a O H ⟶ N a B r O_{3} + N a B r + H_{2} O$ , the n-factor is:

11

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28

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61

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\frac{5}{3}

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Solution

The correct option is D $\frac{5}{3}$
Equivalent weight of ${B r}_{2} = \frac{6 [{B r}_{2}]}{10} = \frac{3}{5}$
n-factor $= \frac{5}{3}$

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