For the reaction $C_{2} H_{6} (g) + n O_{2} ⟶ C O_{2} (g) + H_{2} O (l)$ , the ratio of the coefficients of $C O_{2}$ and $H_{2} O$ is:

1:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2:3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3:2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
2:3

The balanced equation is: $2 C_{2} H_{6} + 7 O_{2} ⟶ 4 C O_{2} + 6 H_{2} O$ . As you can see - the ratio of the coefficients of $C O_{2}$ and $H_{2} O$ is 4:6 or 2:3.

Suggest Corrections

Similar questions

For the reaction $C_{2} H_{6} (g) + n O_{2} ⟶ C O_{2} (g) + H_{2} O (l)$ , the ratio of the coefficients of $C O_{2}$ and $H_{2} O$ is:

C_{2} H_{6} (g) + n O_{2} \to C O_{2} (g) + H_{2} O (I)

C O_{2}

H_{2} O

C_{2} H_{6} (g) + n O_{2} (g) \to C O_{2} (g) + H_{2} O (l)

C O_{2}

H_{2} O

C_{2} H_{6} (g) + n O_{2} \to C O_{2} (g) + H_{2} O (I)

C O_{2}

H_{2} O

C_{2} H_{6} (g) + n O_{2} \to C O_{2} (g) + H_{2} O (I)

C O_{2}

H_{2} O

Join BYJU'S Learning Program