For the reaction- C- O2- CO2- - H-393 J 2Zn - O2- 2ZnO- - H-412J JWhich one is correct-

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Properties of Oxygen

For the react...

Question

For the reaction,
$C + O_{2} ⟶ C O_{2}; Δ H = - 393 J$
$2 Z n + O_{2} ⟶ 2 Z n O; Δ H = - 412 J J$
Which one is correct?

Carbon cannot reduce ZnO to Zn.

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Oxidation of carbon is not feasible.

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Oxidation of Zn is not feasible.

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Zn liberates more heat than carbon during oxidation.

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Solution

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For the reactions

$C + O_{2} \to C O_{2};$ $Δ H = - 393 J$

$2 Z n + O_{2} \to 2 Z n O;$ $Δ = - 412 J$

C + O_{2} ⟶ C O_{2}; Δ H^{\circ} = - x k J

2 C O + O_{2} ⟶ 2 C O_{2}; Δ H^{\circ} = - y k J

C_{(g r a p h i t e)} + \frac{1}{2} O_{2} \to C O; Δ H = - 110.5 k J

C O + \frac{1}{2} O_{2} \to {C O}_{2}; Δ H = - 283.2 k J

C_{(g r a p h i t e)} + O_{2} \to {C O}_{2}

From the thermochemical reactions,

C + 1/2O₂ → CO; ∆H = -110.5 kJ

CO + 1/2O₂→ CO₂; ∆H = -283.2 kJ

The heat of reaction C + O₂ → CO₂ is:

Z n

Z n S

Z n S

Z n O

Z n

2ZnS+3O2→2ZnO+2SO2 (Yield: 62.5 \%)

ZnO+H2SO4→ZnSO4+H2O (Yield: 80 \%)

2ZnSO4+2H2O→2Zn+2H2SO4+O2 (Yield: 80\%)

Z n S

2

Z n

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