Question

For the reaction,

C+ O${}_2\to$ CO${}_2$

Which of the following option is correct?

• A. $\Delta$H > $\Delta$E
• B. $\Delta$H < $\Delta$E
• C. $\Delta$H = $\Delta$E
• D. $\Delta$H = $0$

Answer 1

The correct option is C $\Delta$H = $\Delta$E

$C\left(s\right)+O_2\left(g\right)⟶C{O}_2\left(g\right)$
$[\Delta n_g$ = difference in the number of moles of gas of reactants and products$]$

$\Delta n_g=\Delta n_g\left(product\right)-\Delta n_g\left(reactant\right)$

$\Delta n_g=0$
$\therefore \Delta H=\Delta E+\Delta n_{g}RT$
Since $\Delta n_g=O$,
$\Delta H=\Delta E$

Hence, option $C$ is correct.