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Standard XII

Chemistry

Characteristics of Equilibrium Constant

For the react...

Question

For the reaction, $C a {C O}_{3} (s) ⇌ C a O (s) + {C O}_{2} (g)$ , $K_{p} = 1.16 a t m$ at $800^{o} C$ . If $20.0 g$ of $C a {C O}_{3}$ were kept in a $10 L$ container and heated up to $800^{o} C$ , what percentage of $C a {C O}_{3}$ would remain unreacted at equilibrium?

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Solution

$K_{p} = p_{C O_{2}} = 1.16 a t m$

$N_{C O_{2}} = \frac{p_{C O_{2}} \times V}{R T} = 0.132 m o l$

$N_{C a C O_{3}} (i n i t i a l) = 20 / 100 = 0.2 m o l$

$% C a C O_{3} r e m a i n i n g = \frac{N_{C a C O_{3}} - N_{C O_{2}}}{N_{C a C O_{3}}} \times 100 = 34 %$

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Q. For the reaction :

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For the reaction, CaCO3(s)⇌CaO(s)+CO2(g), Kp=1.16 atm at 800oC. If 20.0 g of CaCO3 were kept in a 10 L container and heated up to 800oC, what percentage of CaCO3 would remain unreacted at equilibrium?

Kp=pCO2=1.16atmNCO2=pCO2×VRT=0.132molNCaCO3(initial)=20/100=0.2 mol% CaCO3 remaining=NCaCO3−NCO2NCaCO3×100=34%

For the reaction, $C a {C O}_{3} (s) ⇌ C a O (s) + {C O}_{2} (g)$ , $K_{p} = 1.16 a t m$ at $800^{o} C$ . If $20.0 g$ of $C a {C O}_{3}$ were kept in a $10 L$ container and heated up to $800^{o} C$ , what percentage of $C a {C O}_{3}$ would remain unreacted at equilibrium?

$K_{p} = p_{C O_{2}} = 1.16 a t m$

$N_{C O_{2}} = \frac{p_{C O_{2}} \times V}{R T} = 0.132 m o l$

$N_{C a C O_{3}} (i n i t i a l) = 20 / 100 = 0.2 m o l$

$% C a C O_{3} r e m a i n i n g = \frac{N_{C a C O_{3}} - N_{C O_{2}}}{N_{C a C O_{3}}} \times 100 = 34 %$