You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Characteristics of Equilibrium Constant

For the react...

Question

For the reaction : $C a C O_{3}$ (s) $\leftrightarrow$ CaO(s) $^{+}$ $C O_{2} (g)$ , $K_{p}$ = 1 atm at $927^{0} C$ . If 20g of $C a C O_{3}$ were kept in a 10 litre vessel at $927^{0} C$ , then calculate percentage of $C a C O_{3}$ remaining at equilibrium.

Open in App

Solution

moles $C a C O_{3} (s) ⟶ C a O (s) + C O_{2} (g)$
at $t = 0$ $\frac{20}{100}$ - -
$0.2 - x$ $x$ $x$
as $K_{P} = [P_{C O_{2}}] = 1$
Thus, by using $P V = n R T$
$\Rightarrow 1 \times 10 L = n \times 0.0821 \times 1200 K$
$\Rightarrow n = 0.1015 = x$
Thus, moles of $C O_{2}$ formed is $x = - 0.1015$
Mole of $C a C O_{3}$ remained= $0.2 - x = 0.2 - 0.1015$
$= 0.0984$ mole
Amount of $C a C O_{3}$ remained is
$0.0984$ moles $\times 100 g / m o l e$
$m_{C a C O_{3}} = 9.84 g$

Suggest Corrections

Similar questions

Q. For the reaction :

C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g), K_{p} = 1

atm at

927^{o} C

. If 20g of

C a C O_{3}

were kept in a 10 litre vessel at

927^{o} C

, then calculate percentage of

C a C O_{3}

remaining at equilibrium:

Q. For the reaction :

C a C O_{3} (S) ⇌ C a O (s) + C O_{2} (g), K_{p} = 1

atm at

927^{0} C

. If

20

g of

C a C O_{3}

were kept in a

10

litre vessel at

927^{0}

C, then percentage of

C a C O_{3}

remaining at equilibrium is closest to:

Q. For the reaction:

C a C O_{3}

(s)

⇌

CaO(s) +

C O_{2}

(g).

K_{p}

= 1 atm at

927^{0}

C. If 20g of

C a C O_{3}

were kept in a 10 liter vessel at

927^{0}

C, then calculate percentage of

C a C O_{3}

remaining at equilibrium:

Q. For the reaction,

C a {C O}_{3} (s) ⇌ C a O (s) + {C O}_{2} (g)

K_{p} = 1.16 a t m

800^{o} C

. If

20.0 g

C a {C O}_{3}

were kept in a

10 L

container and heated up to

800^{o} C

, what percentage of

C a {C O}_{3}

would remain unreacted at equilibrium?

C a C O_{3 (s)} ⇌ C a O_{(s)} + C O_{2 (g)}

;

K_{p} = 1.64 a t m

1000 K

50 g

C a C O_{3}

in a

10

litre closed vessel is heated to

1000 K

. Percentage of

C a C O_{3}

that remains unreacted at equilibrium is :
(Given

R = 0.082 L a t m K^{- 1} {m o l}^{- 1}

)

Join BYJU'S Learning Program

For the reaction : CaCO3 (s) ↔ CaO(s) + CO2(g), Kp = 1 atm at 9270C. If 20g of CaCO3 were kept in a 10 litre vessel at 9270C, then calculate percentage of CaCO3 remaining at equilibrium.

moles CaCO3(s)⟶CaO(s)+CO2(g)at t=0 20100 - - 0.2−x x xas KP=[PCO2]=1Thus, by using PV=nRT⇒1×10L=n×0.0821×1200K⇒n=0.1015=xThus, moles of CO2 formed is x=−0.1015Mole of CaCO3 remained= 0.2−x=0.2−0.1015=0.0984 moleAmount of CaCO3 remained is0.0984 moles ×100g/molemCaCO3=9.84g

For the reaction : $C a C O_{3}$ (s) $\leftrightarrow$ CaO(s) $^{+}$ $C O_{2} (g)$ , $K_{p}$ = 1 atm at $927^{0} C$ . If 20g of $C a C O_{3}$ were kept in a 10 litre vessel at $927^{0} C$ , then calculate percentage of $C a C O_{3}$ remaining at equilibrium.