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Le Chatelier's Principle for Del N Lesser Than Zero

For the react...

Question

For the reaction : $C a C O_{3} (S) ⇌ C a O (s) + C O_{2} (g), K_{p} = 1$ atm at $927^{0} C$ . If $20$ g of $C a C O_{3}$ were kept in a $10$ litre vessel at $927^{0}$ C, then percentage of $C a C O_{3}$ remaining at equilibrium is closest to:

50%

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40%

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20%

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60%

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Solution

The correct option is A 50%
$C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g)$ $K_{p} = 1 a t m$
$20 g$ of $C a C O_{3}$ were kept in $10 L$ vessel
Molecular mass of $C a C O_{3} = \frac{20}{100} = 0.2 m o l$
Molarity of $C a C O_{3} = \frac{0.2}{10} = 0.02 L t .$
$C a C O_{3} ⇌ C a O + C O_{2}$
At $t = 0,$ $0.02$ $0$ $0$
At eqm, $0.02 - x$ $x$ $x$
$K_{P} = P_{C O_{2}}$
$\Rightarrow 1 = x \times 0.082 \times 1200$
$∴ x = 0.01$
Unreacted= $0.02 - 0.01 = 0.01$
$∴$ percentage= $\frac{0.01}{0.02} \times 100 = 50$ %

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