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Gay Lussac's Law, Avagadro's Law

.For the reac...

Question

.For the reaction $C O + 2 H_{2} \Leftrightarrow C H_{3} O H$ , $H_{2}$ is introduced into a 5 litre flask at $327^{\circ} C$ containing 0.2 mole of CO and a catalyst till the pressure is 4.92 atm. At this point 0.1 mole of $C H_{3} O H$ is formed. Calculate $K_{c}$ and $K_{p}$ :

A

27.964

l i t^{2} m o l^{- 2}

& 1.55

a t m^{- 2}

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B

279.77

l i t^{2} m o l^{- 2}

& 0.115

a t m^{- 2}

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C

27.964

l i t^{2} m o l^{- 2}

& 0.155

a t m^{- 2}

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D

2.79

l i t^{- 2} m o l^{- 2}

& 0.155

a t m^{- 2}

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Solution

The correct option is B 279.77 $l i t^{2} m o l^{- 2}$ & 0.115 $a t m^{- 2}$
correct ans is B

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Similar questions

Q. The partial pressures of

{C H}_{3} O H, C O

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in the equilibrium mixture for the reaction

C O + 2 H_{2} ⇌ {C H}_{3} O H

427^{o} C

2.0, 1.0

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C O

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Q. For the reaction,

C O (g) + 2 H_{2} (g) ⇋ {C H}_{3} O H (g)

, hydrogen gas is introduced into a

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Q. The value of

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C O (g) + H_{2} O (g) ⇌ C O_{2} (g) + H_{2} (g)

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Q. 0.1 moles of ethane gas

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Q. 0.1 moles of ethane gas

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and 0.3 moles of oxygen gas are sealed in a flask at

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Calculate the partial pressure of the products of the reaction in the reaction mixture.

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