Question

For the reaction $CO\left(g\right)+2H_2\left(g\right)\leftrightharpoons {CH}_{2}OH\left(g\right)$. If active mass of $CO$ is kept constant and active mass of $H_2$ is tripled, the rate of forward reaction will become:

• A. three times
• B. six times
• C. eight times
• D. nine times

Answer 1

The correct option is D nine times

$CO\left(g\right)+2H_2\left(g\right)\rightleftharpoons {CH}_{2}OH\left(g\right)$

safe of forward reaction $=K_f\left[CO\right]{\left[H_2\right]}^2$

if $\left[CO\right]=constant+\left[H_2\right]tripled$

$r_{2}new=K_f\left[CO\right]{\left[{3H}_2\right]}^2=9K_f\left[CO\right]{\left[H_2\right]}^2$$⟹$ Hence 9 times.