Question

For the reaction $CO\left(g\right)+2H_2\left(g\right)\rightleftharpoons {CH}_{3}OH\left(g\right)$. If active mass of $CO$ is kept constant and active mass of $H_2$ is tripled, the rate of forward reaction will become ______ of its initial value.

• A. three times
• B. six times
• C. eight times
• D. nine times

Answer 1

The correct option is D nine times

For the following reaction, Rate is defined as

$rate=k\left[CO\right][H_2{]}^2$

Now, the active mass of CO is kept constant and active mass of {H}_{2} is tripled. Now the rate is,

${rate}^{{}^{\prime }}=k\left[CO\right][3\times H_2{]}^2$

${rate}^{{}^{\prime }}=9\times rate$

So, the rate of forward reaction will become nine times of its initial value.