Question

For the reaction, $A+2B\to C$, $5$ moles of A and $8$ moles of B will produce :

• A. 5 moles of C
• B. 4 moles of C
• C. 8 moles of C
• D. 12 moles of C

Answer 1

The correct option is B 4 moles of C

B) 4 Mole of C.

According to the reaction, 5 moles of A will need 10 moles of B to completely react with B and give C but we have only 8 moles of B.

So B is the limiting agent here.

Hence 8 moles of B react with 4 moles of A to give 4 moles of C because the stoichiometric of A and C are the same.