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Question

For the reaction,
FeS2+KMnO4+H+Fe3++H2SO4+Mn2++H2O.
If the molar mass of FeS2 is M, then equivalent mass of FeS2 would be equal to:

A
M
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B
M10
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C
M11
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D
M15
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Solution

The correct option is D M15
+21FeS22H2+6SO4++3Fe3+ oxidation half reaction
nfactor=[1×(32)+2(6(1)]=15
( n factor of a compound undergoing redox change is equal to no. of moles of electrons lost, gained or exchange by 1 mole of the compound.)
So, eq.wt. of FeS2=M15
Hence, (d) is the correct answer.

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