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Characteristics of Equilibrium Constant

For the react...

Question

For the reaction given below $Δ G^{\circ} = + 1.7 k J .$ What is the equilibrium constant at $25^{0} C$ for the same reaction:
$2 H I (g) ⇌ H_{2} (g) + I_{2} (g)$

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3.9

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0.5

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Solution

The correct option is C 0.5
$Δ G^{o} = + 1.7 k J \Rightarrow 1700 J$

$Δ G^{o} = - R T l n K_{e q} \Rightarrow K_{e q} = e^{- Δ G / R T}$

$R = 8.314 J m o l^{- 1} k J$

$T$ in kelvin

$T = 25^{o} C = 298.15 K$

$K_{e q} = e \frac{- (1.7) \times 10^{3}}{8.314 \times 298.15} = 0.5$

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Similar questions

Δ G^{o}

1.7 k J

2 H I (g) ⇌ H_{2} (g) + I_{2} (g)

25^{\circ} C

Δ G (H I : g) \equiv + 1.7 k J .

25^{o} C

2 H I (g) ⇌ H_{2} (g) + I_{2} (g)

H_{2_{(g)}} + I_{2_{(g)}} ⇌ {2 H I}_{(g)}

{2 H I}_{(g)} ⇌ H_{2_{(g)}} + I_{2_{(g)}}

\frac{1}{2} H_{2} (g) + \frac{1}{2} I_{2} (g) ⇌ H I (g) is K_{c}

2 H I (g) ⇌ H_{2} (g) + I_{2} (g)

500

K_{c}

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\frac{1}{2} H_{2 (g)} + \frac{1}{2} I_{2 (g)} ⇌ H I_{(g)}

K_{c}

2 H I_{(g)} ⇌ H_{2 (g)} + I_{2 (g)}

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