For the reaction given below the values of standard Gibbs free energy of formation at 298 K are given. What is the nature of the reaction? I2+H2S→2HI+S ΔG0f(HI)=1.8kJmol−1, ΔG0f(H2S)=33.8kJmol−1
A
Non-spontaneous in forward direction
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B
Spontaneous in forward direction
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C
Spontaneous in backward direction
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D
Non-spontaneous in both forward and backward directions
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Solution
The correct option is C Spontaneous in forward direction I2+H2S→2HI+S ΔG0=∑G0f(products)−∑G0f(Reactants) = -30.2 kJ Hence, the reaction is spontaneous in forward direction.