For the reaction $H_{2} (g) + B r_{2} (g) \to 2 H B r (g)$ , the experiment data suggested that $r = k [H_{2}] [B r_{2}]^{1 / 2}$ . The molecularity and order of the reaction are respectively:

2, 3/ 2

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3/2 , 3/2

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Not defined, 3/2

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1, 1/2

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Solution

The correct option is A 2, 3/ 2
H $_{2}$ (g) + Br $_{2}$ (g) $\to$ 2HBr (g)

r = k[H $_{2}$ ] [Br $_{2}$ ] $^{1 / 2}$

Molecularity =2

Order= 1+0.5=1.5=3/2

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r a t e = K [H_{2}] [B r_{2}]^{1 / 2}

H_{2} (g) + B r_{2} (g) \to 2 H B r (g)

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r = k [H_{2}] [B r_{2}]^{1 / 2}

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