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Question

For the reaction H2(g) + 12O2(g) H2O(l),ΔH = 285.8kJmol1 ΔS = 0.163kJmol1K1. What is the value of free energy change 27C for the reaction.


A

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B

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C

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D

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Solution

The correct option is A


ΔG = ΔT TΔS,T = 27 + 273 = 300K

ΔG = (285.8) (300)(0.163) = 236.9kJmol1


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