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Question

For the reaction, H2+I22HI,K=47.6. If the initial number of moles of each reactant and product is 1 mole, then at equilibrium:

A
[I2]=[H2],[I2]>[HI]
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B
[I2]=[H2],[I2]<[HI]
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C
[I2]<[H2],[I2]=[HI]
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D
[I2]>[H2],[I2]=[HI]
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Solution

The correct option is B [I2]=[H2],[I2]<[HI]
For the given reaction , K=[HI]2[H2][I2]

As one mole of H2 reacts with 1 mole of I2 , even at equilibrium , [H2]=[I2]

Hence, K=[HI]2[I2]2 or K=[HI][I2]=47.6

i.e , [HI]>[I2]

Hence, option B is correct.

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