Question

For the reaction $H_{2}O\left(s\right)\leftrightharpoons H_{2}O\left(l\right)$ at 0°C and normal pressure

• A. H > TS
• B. H = TS
• C. H = G
• D. H < TS

Answer 1

The correct option is B

H = TS

Let's look at the reaction.
$H_{2}O\left(s\right)\leftrightharpoons H_{2}O\left(l\right)$ at $0^{\circ }C$
It will be in equilibrium at $0^{\circ }C$
Now, At equilibrium
$△$G = 0
&$△$G = $△$H - T$△$S
$\Rightarrow △$H - T$△$S = 0
$\Rightarrow △H=T△S$