For the reaction, $H_{3} P O_{2} + N a O H \to N a H_{2} P O_{2} + H_{2} O$ What is the equivalent weight of $H_{3} P O_{2}$ ? (mol. wt. is M)

M

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\frac{M}{2}

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\frac{M}{3}

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None of these

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Solution

The correct option is A $M$
As $H_{3} P O_{2}$ is a monobasic acid. $∴ n - f a c t o r = 1$ .
Equivalent weight $= \frac{M o l e c u l a r w e i g h t / A t o m i c w e i g h t}{n - f a c t o r} = M / 1 = M$ .

Suggest Corrections

Similar questions

H_{3} P O_{2}

P H_{3}

H_{3} P O_{3}

M

H_{3} P O_{4} - ------ - + C a (O H)_{2} ⟶ C a H P O_{4} + 2 H_{2} O

H_{3} P O_{2} - ------ - + N a O H ⟶ N a H_{2} P O_{2} + H_{2} O

N a H C_{2} O_{4} - ---------- - + N a O H ⟶ N a_{2} C_{2} O_{4} + H_{2} O

H_{3} {P O}_{2} + N a O H ⟶ {N a H}_{2} {P O}_{2} + H_{2} O

H_{3} {P O}_{2}

N a_{2} S_{2} O_{3}

2 N a_{2} S_{2} O_{3} + I_{2} \to N a_{2} S_{4} O_{6} + 2 N a I

H_{3} P O_{2} \to P H_{3} + H_{3} P O_{3}

H_{3} P O_{2}

H_{3} P O_{2}

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