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Question

For the reaction HA+H2OA+H3O+
The value of Ka is 6. Find the value of pKa.

A
1×106
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B
1×108
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C
1×108
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D
none of these
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Solution

The correct option is C 1×106
Acids differ in their H+ donating ability. Measured based on their ability to donate H+ to water
HA+H2OA+H3O+
Position of the equilibrium relates to acid strength
pKa=logka
6=logka
ka=1×106

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