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For the react...

Question

For the reaction,
$M^{x +} + M n O_{4}^{-} \to M O_{3}^{-} + M n^{2 +}$
If one mole of $M n O_{4}^{-}$ oxidises 1.67 moles of $M^{x +}$ to oxidation state where its magnet moment is 1.73. Find x. ___

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Solution

gram equivalents of $M^{x +}$ = gram equivalents of $M n O_{4}^{-}$
1 $\times$ 5 = 1.67 $\times$ a
a = 3
i.e. n-factor for $M^{x +} \to M O_{3}^{-}$ is 3 then value of x = 2

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