Question

For the reaction, $N_2+3H_2\rightleftharpoons 2N{H}_3$ in a vessel, after the addition of equal numbers of mole of $N_2$ and $H_2$, equilibrium state is formed.

Which of the following is correct?

• A. $\left[H_2\right]=\left[N_2\right]$
• B. $\left[H_2\right]<\left[N_2\right]$
• C. $\left[H_2\right]>\left[N_2\right]$
• D. $\left[H_2\right]>\left[N{H}_3\right]$

Answer 1

Answer: (B)

$\left[H_2\right]<\left[N_2\right]$

Reaction:
$N_2+3H_2\rightleftharpoons 2N{H}_3$
$aa$
1 3
$(a-x)(a-3x)2x$
1 mole of $N_2$ reacts with 3 mole of $H_2$ thus, for
$(a-x)>(a-3x)$
$\left[H_2\right]<\left[N_2\right]$