Question

For the reaction, $N_2+3H_2\to 2N{H}_3$ under certain conditions of P and T, the rate of formation of $N{H}_3$ is 0.001 $kgh{r}^{-1}$. The rate of conversion of $H_2$ under these conditions is $x\times {10}^{-4}$ kg $h{r}^{-1}$. $100x$ is____________.

Answer 1

$-\frac{1}{3}\frac{d{H}_2}{dt}=\frac{1}{2}\frac{dN{H}_3}{dt}$
Hence, $-\frac{d{H}_2}{dt}=\frac{3}{2}\frac{dN{H}_3}{dt}=\frac{3}{2}\times 0.001kg/hr=0.15\times {10}^{-4}kg/hr=x\times {10}^{-4}kg/hr$
Hence, $x=0.15$
$100x=100\times 0.15=15$