Question

For the reaction $N_2+3H_2\rightleftharpoons 2N{H}_3$ the rate of change of concentration for hydrogen is $-0.3\times {10}^{-4}M{s}^{-1}.$ The rate of change of concentration of ammonia is :

• A. (A)$-0.2\times {10}^{-4}$
• B. (B)$0.2\times {10}^{-4}$
• C. (C)$0.1\times {10}^{-4}$
• D. (D)$0.3\times {10}^{-4}$

Answer 1

The correct option is B (B)$0.2\times {10}^{-4}$

The rate of change of concentration for hydrogen $=\frac{d\left[H_2\right]}{dt}=-0.3\times {10}^{-4}M{s}^{-1}$
The rate of change of concentration of ammonia $\frac{d\left[N{H}_3\right]}{dt}=\frac{2}{3}\times -\frac{d\left[H_2\right]}{dt}=\frac{2}{3}\times -(-0.3\times {10}^{-4}M{s}^{-1})=0.2\times {10}^{-4}$