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Question

For the reaction N2+3X22NX3 where X=F,Cl (the average bond energies are FF=155kJ mol1,NF=272kJ mol1,ClCl kJ mol1,NCl kJ mol1 and NN=941 kJmol1).
The heats of formation of NF3 and NCl3 in kJ mol1, respectively, are closest to


  1. – 226 and + 467

  2. + 226 and –467

  3. –151 and + 311

  4. + 151 and -311


Solution

The correct option is A

– 226 and + 467


 – 226 kJ and 467 kJ are heat of reaction not heat of formation.

ΔHr=ϵNN+3×ϵxx2[3×ϵNx]

ΔHr=ϵNN+3×ϵFF2×3×ϵNF

=941+3×1556×272ΔHr=226kJ

ΔHr=ϵNN+3ϵClCl6×ϵNCl=941+3×2426×200=467 kJ

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