Question

For the reaction

$N_2\left(g\right)+3H_2\left(g\right)\to 2N{H}_3\left(g\right)$

• A. $\Delta H=\Delta E+RT$
• B. $\Delta H=\Delta E-RT$
• C. $\Delta H=\Delta E+2RT$
• D. $\Delta H=\Delta E-2RT$

Answer 1

The correct option is D $\Delta H=\Delta E-2RT$

$N_2\left(g\right)+3H_2\left(g\right)\to 2N{H}_3\left(g\right)$
$\Delta H=\Delta E+\Delta n_{g}RT$
Now,
$\Delta n_g=2-3-1$
$\Delta n_g=-2$
$\therefore \Delta H=\Delta E-2RT$