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Question

For the reaction N2(g)+3H2(g)2NH3(g),ΔH=93.6 kJ mol1. The amount (i.e. number of mole) of~H2 at equilibrium will
increase if


A

Volume is increased

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B

Volume is decreased

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C

is added at constant volume

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D

is removed.

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Solution

The correct option is B

Volume is decreased


We have Kc=(nNH3/V)2(nN2/V)(nH2/V)3=(nNH3)2(nN2)(nH2)3V2

The above equilibrium constant Kc is a "constant” for a given temperature (also maintained constant unless otherwise mentioned). If V decreases then number of moles of Hydrogen should also decrease.


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