For the reaction N2(g)+3H2(g)⇌2NH3(g),ΔH=−93.6 kJ mol−1. The amount (i.e. number of mole) of~H2 at equilibrium will
increase if
Volume is decreased
We have Kc=(nNH3/V)2(nN2/V)(nH2/V)3=(nNH3)2(nN2)(nH2)3V2
The above equilibrium constant Kc is a "constant” for a given temperature (also maintained constant unless otherwise mentioned). If V decreases then number of moles of Hydrogen should also decrease.