For the reaction- N - 2 g -3 H - 2 g - -rightleftharpoons 2 NH - 3 g triangle H is equal to - U - change in internal energyA- U -2 RTB- - U -2 RTC- U - RTD- U - RT

The correct option is A U 2RTWe know that, H = U + n_g RT For the reaction: nbsp; N_2(g) + 3H_2(g) ⇌ 2NH_3(g) n_g = 2 4 = 2 H= U + n_gRT H= U + ( 2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Enthalpy

For the react...

Question

For the reaction,
$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g), △ H$ is equal to :
( $△ U$ = change in internal energy)

△ U + 2 R T

No worries! We‘ve got your back. Try BYJU‘S free classes today!

△ U - 2 R T

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

△ U + R T

No worries! We‘ve got your back. Try BYJU‘S free classes today!

△ U - R T

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $△ U - 2 R T$
We know that,
$△ H = △ U + △ n_{g} R T$
For the reaction:
$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)$
$△ n_{g} = 2 - 4 = - 2$
$△ H = △ U + △ n_{g} R T$
$△ H = △ U + (- 2) R T$
$△ H = △ U - 2 △ R T$

Suggest Corrections

Similar questions

Q. For

N_{2} (g) + 2 H_{2} (g) ⇌ 2 N H_{3} (g)

Δ H

is equal to:

Q. For

2 S O_{2} (g) + O_{2} (g) \to 2 S O_{3} (g)

Δ H

is equal to:

Q. For the reaction,

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g), △ H

is equal to :
(

△ U

= change in internal energy)

Q. If

f^{2} (x) + 2 g^{2} (x) + 3 h^{2} (x) \leq 1

and

u (x) = 2 f (x) - 2 g (x) + 3 h (x),

then the maximum value of

u^{2} (x)

is equal to

For the reaction, N₂ + 3H₂ ⇌ 2NH₃, ∆H= …………….

Join BYJU'S Learning Program

Explore more

Enthalpy

Standard XII Chemistry

Join BYJU'S Learning Program

For the reaction, N2(g)+3H2(g)⇌2NH3(g),△H is equal to : (△U = change in internal energy)

The correct option is B △U−2RTWe know that, △H=△U+△ngRT For the reaction: N2(g)+3H2(g)⇌2NH3(g) △ng=2−4=−2 △H=△U+△ngRT △H=△U+(−2)RT △H=△U−2△RT

For the reaction,
$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g), △ H$ is equal to :
( $△ U$ = change in internal energy)

The correct option is B $△ U - 2 R T$
We know that,
$△ H = △ U + △ n_{g} R T$
For the reaction:
$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)$
$△ n_{g} = 2 - 4 = - 2$
$△ H = △ U + △ n_{g} R T$
$△ H = △ U + (- 2) R T$
$△ H = △ U - 2 △ R T$