For the reaction $N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g), △ H = - 93.6 k J m o l^{- 1} .$ The concentration of $H_{2}$ at equilibrium will increase if

the temperature is decreased

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the volume of the system is decreased

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N_{2}

is added at constant volume

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N H_{3}

is added

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Solution

The correct option is D $N H_{3}$ is added
From Le-chatelier principle,
For an exothermic reaction, the heat of reaction will be released, if temperature is increased the reaction will shift in backward direction and favour reactant.
When the volume of the system is increase, the reaction will shift to that direction which have lower number of moles.
Simlarly, if reactants ( $N_{2} a n d H_{2}$ is added the reaction will shift towards forward reaction.
and if $N H_{3}$ (g) is added the reaction will shift toward the production of reactants

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Similar questions

Q. Assertion :For reaction

N_{2} (g) + 3 H_{2} (g) ⇌ 2 {N H}_{3} (g)

Unit of

K_{C} = L^{2} {m o l}^{- 2}

Reason: For the reaction

N_{2} (g) + 3 H_{2} (g) ⇌ 2 {N H}_{3} (g)

, Equilibrium constant

K_{C} = \frac{{[{N H}_{3}]}^{2}}{[N_{2}] {[H_{2}]}^{3}}

Q. If the temperature is increased, how will the equilibrium of the following reaction be affected ?

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g); △ H = - 30 k J / m o l

For the reaction $N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g), Δ H = - 93.6 k J m o l^{- 1}$ . The concentration of $H_{2}$ at equilibrium will increase if

Q. The equilibrium constant for the reaction:

N_{2 (g)} + 3 H_{2 (g)} ⇌ 2 {N H}_{3 (g)}

715 K

, is

6.0 \times 10^{- 2}

. If, in a particular reaction, there are

0.25 m o l L^{- 1}

H_{2}

and

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{N H}_{3}

present, calculate the concentration of

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Q. A tenfold increase in pressure on the reaction

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

at equilibrium constant

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will :

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For the reaction N2(g)+3H2(g)⇌2NH3(g),△H=−93.6 kJ mol−1. The concentration of H2 at equilibrium will increase if

For the reaction $N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g), △ H = - 93.6 k J m o l^{- 1} .$ The concentration of $H_{2}$ at equilibrium will increase if