Question

For the reaction $N_2$+ $O_2$ $\leftrightharpoons$2 NO equilibrium constant is $K_c$

Now if we multiply across the given equation by a constant say 3, the new equilibrium constant is ${K_c}^3$(previous equilibrium raised to the power of the constant 3)

• A. True
• B. False

Answer 1

The correct option is A

True

$N_2$ + $O_2$ $\leftrightharpoons$ $2NO{K}_c$ = $\frac{[NO{]}^2}{\left[N_2\right]\left[O_2\right]}$

3 $\times [N_2+O_2\leftrightharpoons$ 2NO]

Becomes 3 $N_2$ + 3 $O_2$ $\leftrightharpoons$ 6NO

The Equilibrium constant $K_{new}$ = $\frac{[NO{]}^6}{\left[N_2{]}^3\right[O_2{]}^3}$ = ${K_c}^3$