Question

For the reaction $N_2{O}_{4\left(s\right)}\to 2N{O}_{2\left(g\right)}$ the degree of dissociation at equilibrium is $0.2$ at $1atm$. Then $K_p$ will be:

• A. $\frac{1}{2}$
• B. $\frac{1}{4}$
• C. $\frac{1}{6}$
• D. $\frac{1}{8}$

Answer 1

Answer: (C)

$\frac{1}{6}$

This is $A\to 2B$ type reaction.

$K_P=\frac{4\times 2P}{(1+x)(1-x)}$

$4\left(0.04\right)\left(1.2\right)\left(0.8\right)=0.167=\frac{1}{6}$

Hence, the correct option is $\text{C}$