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Question

For the reaction, N2O5(g)NO2(g)+12O2(g) The value of rate of disappearance of N2O5 is given as 6.25×103molL1s1. The rate of formation of NO2 and O2 is given respectively as:



A

6.25×103molL1s1and6.25×103molL1s1

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B

1.25×102molL1s1and3.125×103molL1s1

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C

6.25×103molL1s1and3.125×103molL1s1

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D

1.25×102molL1s1and6.25×103molL1s1

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Solution

The correct option is A

1.25×102molL1s1and3.125×103molL1s1


Rate of disappearance of reactant = rate of appearance of product
Or -1Stoichiometric  coefficient  of reactantd[reactant]dt
+1Stoichiometric  coefficient  of  productd[product]dt
For the reaction,
N2O5(g)2NO2(g)+12O2(g)d[N2O5]dt=+12d[NO2]dt=+2d[O2]dt
d[NO2]dt=2d[N2O5]dt=2×6.25×103molL1s1=12.5×10(3)molL1s1
=1.25×102molL1s1d[O2]dt=d[N2O5]dt×12=6.25×103molL1s12=3.125×103molL1s1


Chemistry

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