Question

For the reaction, $N_2{O}_4\left(g\right)\to 2N{O}_2\left(g\right),$ the correct option is:

• A. ${\Delta }_{r}H>0\text{and}{\Delta }_{r}S<0$
• B. ${\Delta }_{r}H<0\text{and}{\Delta }_{r}S>0$
• C. ${\Delta }_{r}H<0\text{and}{\Delta }_{r}S<0$
• D. ${\Delta }_{r}H>0\text{and}{\Delta }_{r}S>0$

Answer 1

The correct option is D ${\Delta }_{r}H>0\text{and}{\Delta }_{r}S>0$

$N_2{O}_4\left(g\right)\to 2N{O}_2\left(g\right)$
Decomposition reaction of $N_2{O}_4\left(g\right)$ is endothermic, with an increase in gaseous moles,
so $\Delta H>0\text{and}\Delta S>0$.