For the reaction -lfrac-d- N - 2 O - 5- dt - K - 1- N - 2 O - 5- - frac d - NO - 2- dt - K - 2- N - 2 O - 5- 11and -frac d - O - 2- dt - K - 3- N - 2 O - 5- The K 1- K 2 and K 3 are related as -A- K 1- K 2- K 3B- 2 K 1- K 2-4 K 3- 2 K 1-4 K 2- K 3D- K 1-2 K 2-4 K 3

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Enthalpy of Combustion

For the react...

Question

For the reaction :
$N_{2} O_{5} \to 2 N O_{2} + \frac{1}{2} O_{2} \frac{- d [N_{2} O_{5}]}{d t} = K_{1} [N_{2} O_{5}], \frac{d [N O_{2}]}{d t} = K_{2} [N_{2} O_{5}], a n d \frac{d [O_{2}]}{d t} = K_{3} [N_{2} O_{5}]$
The $K_{1}, K_{2}$ and $K_{3}$ are related as :

K_{1} = K_{2} = K_{3}

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2 K_{1} = K_{2} = 4 K_{3}

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2 K_{1} = 4 K_{2} = K_{3}

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K_{1} = 2 K_{2} = 4 K_{3}

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N_{2} O_{5} ⟶ 2 N O_{2} + \frac{1}{2} O_{2}

\frac{- d [N_{2} O_{5}]}{d t} = k_{1} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k_{2} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k_{3} [N_{2} O_{5}]

k_{1}, k_{2}

k_{3}

N_{2} O_{5}

(i) N_{2} O_{5} (g) \to 2 N O_{2} (g) + \frac{1}{2} O_{2} (g); \frac{- d [N_{2} O_{5}]}{d t} = k [N_{2} O_{5}] (i i) 2 N_{2} O_{5} (g) \to 4 N O_{2} (g) + O_{2} (g); \frac{- d [N_{2} O_{5}]}{d t} = k^{'} [N_{2} O_{5}]

2 N_{2} O_{5} (g) \to 4 N O_{2} (g) + O_{2} (g)

- \frac{Δ [N_{2} O_{5}]}{Δ t} = k_{1} [N_{2} O_{5}], + \frac{[N O_{2}]}{Δ t} = k_{2} [N_{2} O_{5}], + \frac{Δ [O_{2}]}{Δ t} = k_{3} [N_{2} O_{5}]

N_{2} O_{5}

(i) N_{2} O_{5} (g) \to 2 N O_{2} (g) + \frac{1}{2} O_{2} (g); \frac{- d [N_{2} O_{5}]}{d t} = k [N_{2} O_{5}] (i i) 2 N_{2} O_{5} (g) \to 4 N O_{2} (g) + O_{2} (g); \frac{- d [N_{2} O_{5}]}{d t} = k^{'} [N_{2} O_{5}]

2 A ⟶ B + 3 C

- \frac{d [A]}{d t} = k_{1} {[A]}^{2}; \frac{d [B]}{d t} = k_{2} {[B]}^{2}; \frac{d [A]}{d t} = k_{3} {[A]}^{2}

k_{1}, k_{2}

k_{3}

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