For the reaction NO2-CO- CO2-NO the experimental rate expression is -dc-dt-k-NO2-2 the number of molecules of CO involves in the slowest step will be-

The correct option is A 0The number of molecules of CO involves in the slowest step will nbsp;be 0 because CO is not involve in the slowest step i.e. rate ...

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Standard XII

Chemistry

Hess' Law

For the react...

Question

For the reaction $N O_{2} + C O \to C O_{2} + N O$ the experimental rate expression is $- \frac{d c}{d t} = k [N O_{2}]^{2}$ the number of molecules of CO involves in the slowest step will be:

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Solution

The correct option is A 0
The number of molecules of CO involves in the slowest step will be 0 because CO is not involve in the slowest step i.e. rate determing step.

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Similar questions

Q. Following reaction takes place by mechanism

N O_{2} + C O \to N O + C O_{2}

S t e p I N O_{2} + N O_{2} k_{1}, s l o w - --- \to N O_{3} + N O

S t e p I I N O_{3} + C O k_{2}, f a s t - --- \to N O_{2} + C O_{2}

Hence,

(\frac{d x}{d t})

for the given reaction is:

Q. Assertion :In the reaction,

N O_{2} (g) + C O (g) ⟶ C O_{2} (g) + N O (g)

, rate

= k {[N O_{2}]}^{2}

.
The rate of reaction does not depend on the concentration of

C O

. Reason: Carbon monoxide is involved in fast step.

Calculate the total number of molecules that will possess fractional bond order among the following molecules
$O_{2}^{2 +}, N_{2}^{2 +}, O_{2}^{+}, N O, C O, C O^{+}, O_{2}^{-}, N O^{2 +}, C N^{-}, N O^{2 -}, N_{2}^{-}$

Q. The rate law for the dimerisation of

N O_{2}

\frac{- d [N O_{2}]}{d t} = k [N O_{2}]^{2}

.
Which of the following changes will change the value of the specific rate constant (k)?

Q. Derive an expression for the Rate (k) of reaction :

2 N_{2} O_{5} (g) \to 4 N O_{2} (g) + O_{2} (g)

With the help of following mechanism:

N_{2} O_{5}_{a} N O_{2} + N O_{3}

N O_{3} + N O_{2}_{- a} N_{2} O_{5}

N O_{2} + N O_{3}_{b} N O_{2} + O_{2} + N O

N O + N O_{3}_{c} 2 N O_{2}

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For the reaction NO2+CO→CO2+NO the experimental rate expression is −dcdt=k[NO2]2 the number of molecules of CO involves in the slowest step will be:

The correct option is A 0The number of molecules of CO involves in the slowest step will be 0 because CO is not involve in the slowest step i.e. rate determing step.

For the reaction $N O_{2} + C O \to C O_{2} + N O$ the experimental rate expression is $- \frac{d c}{d t} = k [N O_{2}]^{2}$ the number of molecules of CO involves in the slowest step will be:

The correct option is A 0
The number of molecules of CO involves in the slowest step will be 0 because CO is not involve in the slowest step i.e. rate determing step.