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Standard XII

Chemistry

Order of Reaction

For the react...

Question

For the reaction $O_{3 (g)} + O_{(g)} \to 2 O_{2 (g)}$ , if the rate law expression is, rate $= K [O_{3}] [O]$ the molecularity and order of the reaction are:

2

and

2

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2

and

1.33

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2

and

1

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1

and

2

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Solution

The correct option is A $2$ and $2$
Rate = $K [O_{3}] [O]$
Order $= 1 + 1 = 2$ .
Hence, the overall order of the reaction is 2.
Now,
${O_{3}}_{(9)} + O_{(9)} \to {2 O}_{2}$
There are two molecules of reactants.
And, for simple reactions, the rate of reaction is equal to the molecularity
$∴$ Molecularity = 2.

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Similar questions

Q. Assertion :For the reaction given below, the molecularity of first step is 1 and of second step is 2.

2 O_{3} (g) \to 3 O_{2} (g)

Step 1

O_{3} (g) ⇌ O_{2} (g) + O (g)

Step 2

O_{3} (g) + O s l o w - - \to 2 O_{2} (g)

Reason: O(g) is an intermediate and rate of reaction is

K [O_{3}]^{2} [O_{2}]^{- 1}

and order of reaction is 1.

Q. Statement - I: For the reaction given below:

The molecularity of the first step is 1 and the second step is 2.

2 O_{3} (g) \to 3 O_{2} (g)

Step 1:

O_{3} (g) ⇌ O_{2} (g) + O (g)

Step 2:

O_{3} (g) + O s l o w - - \to 2 O_{2} (g)

Statement - II: O(g) is an intermediate. The rate of reaction is

K [O_{3}]^{2} [O_{2}]^{- 1}

and the order of the reaction is 1.

Q. For the reaction given below,

2 O_{3} (g) \to 3 O_{2} (g)

Step l:

O_{3} (g) \to O_{2} (g) + O (g)

Step 2:

O_{3} (g) + O \to^{s l o w} 2 O_{2} (g)

Statement I: The molecularity of the first step is 1 and of the second step is 2.
Statement-II:

O (g)

is an intermediate and rate of reaction is

K [O_{3}]^{2} [O_{2}]^{- 1}

and order of reaction is 1.

The chemical reaction $2 O_{3} \to 3 O_{2}$ involves two elementary steps :
$O_{3} f a s t - - \to O_{2} + O; O + O_{3} S l o w - -- \to 2 O_{2}$
The differential rate law expression will be :

Q. For a reaction

2 A + 3 B \to

Products,

the rate law expression is given by rate

= K (A)^{1} (B)^{2}

. The order of the reaction with respect to

A, B

and overall order of reaction are:

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For the reaction O3(g)+O(g)→2O2(g), if the rate law expression is, rate =K[O3][O] the molecularity and order of the reaction are:

The correct option is A 2 and 2Rate = K[O3][O]Order =1+1=2.Hence, the overall order of the reaction is 2.Now,O3(9)+O(9) →2O2There are two molecules of reactants.And, for simple reactions, the rate of reaction is equal to the molecularity∴ Molecularity = 2.

For the reaction $O_{3 (g)} + O_{(g)} \to 2 O_{2 (g)}$ , if the rate law expression is, rate $= K [O_{3}] [O]$ the molecularity and order of the reaction are: