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Relation between Kp and Kc

For the react...

Question

For the reaction $P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g)$ at $2500^{\circ} C$ , the value of $K_{C}$ is $26$ , then the value of $K_{P}$ at the same temperature will be

0.61

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0.57

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0.83

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Solution

The correct option is A
0.61

$K_{P} = K_{C} (R T)^{△ n} = 26 (0.0821 \times 523)^{- 1} = 0.61$
$△ n = 1 - 2 = - 1$

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Similar questions

For the reaction $P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g)$ at $2500^{\circ} C$ , the value of $K_{C}$ is $26$ , then the value of $K_{P}$ at the same temperature will be

Q. For the following reaction at

250^{o} C

, the value of

K_{c}

26

, then the value of

K_{p}

at the same temperature will be:

P {C l}_{3} (g) + {C l}_{2} (g) ⇌ P {C l}_{5} (g)

Q. For the reaction

P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g)

the value of

K_{c}

250^{o} C

is 26. The value of

K_{p}

at this temperature will be :

Q. For the reaction

P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g)

, the value of

K_{c}

250^{\circ} C

is 26. The value of

K_{p}

at the same temperature will be:

Q. For reaction

P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g), K_{c}

is 30 at 300 K. The value of

K_{p}

at 300 K is

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For the reaction PCl3(g) + Cl2(g) ⇌ PCl5(g) at 2500∘C, the value of KC is 26, then the value of KP at the same temperature will be

The correct option is A 0.61 KP = KC(RT)△n = 26(0.0821 × 523)−1 = 0.61 △n = 1 – 2 = −1

For the reaction $P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g)$ at $2500^{\circ} C$ , the value of $K_{C}$ is $26$ , then the value of $K_{P}$ at the same temperature will be

The correct option is A
0.61

$K_{P} = K_{C} (R T)^{△ n} = 26 (0.0821 \times 523)^{- 1} = 0.61$
$△ n = 1 - 2 = - 1$