For the reaction PCl3g - Cl2g - PCl5g- the value of Kc at 250- C is 26- The value of Kp at the same temperature will be-

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Le Chatelier's Principle for Del N Greater Than Zero

For the react...

Question

For the reaction $P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g)$ , the value of $K_{c}$ at $250^{\circ} C$ is 26. The value of $K_{p}$ at the same temperature will be:

0.0006

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0.57

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0.61

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0.83

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Solution

The correct option is C $0.61$
The equilibrium reaction is $P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g)$ .

The relationship between $K_{p}$ and $K_{c}$ is $K_{p} = K_{c} (R T)^{Δ n}$ .

$K_{C} = 26, T = 250 + 273 = 523, R = 0.082 L a t m m o l^{- 1} K^{- 1}, Δ n = 1 - (1 + 1) = - 1$ .

Substitute values in the above expression.

$K_{p} = 26 \times (0.082 \times 523)^{- 1} = 0.61$ .

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For the reaction PCl3(g)+Cl2(g)⇌PCl5(g), the value of Kc at 250∘C is 26. The value of Kp at the same temperature will be:

The correct option is C 0.61The equilibrium reaction is PCl3(g)+Cl2(g)⇌PCl5(g).The relationship between Kp and Kc is Kp=Kc(RT)Δn.KC=26,T=250+273=523,R=0.082L atm mol−1K−1,Δn=1−(1+1)=−1.Substitute values in the above expression. Kp=26×(0.082×523)−1=0.61.

For the reaction $P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g)$ , the value of $K_{c}$ at $250^{\circ} C$ is 26. The value of $K_{p}$ at the same temperature will be: