For the Reaction PCl5(g) ⇌ PCl3(g) + Cl2(g) at 400K & 1atm, degree of dissociation of PCl is 0.4. Calculate the vapour density of equilibrium mixture under given condition? ( ) (1) 60.80 (2) 50.10 (3) 74.28 (4) 98.12

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P C l_{5} (g) \to {P C l}_{3} (g) + {C l}_{2} (g)

[A t o m i c w t . o f C l = 35.5; U s e R = 0.08 a t m - l i t r e / K - m o l e]

I . 2 H I_{(g)} ⇌ H_{2 (g)} + I_{2 (g)}

I I . 2 N H_{3 (g)} ⇌ N_{2 (g)} + 3 H_{2 (g)}

I I I . 2 N O_{(g)} ⇌ N_{2 (g)} + O_{2 (g)}

I V . P C l_{5 (g)} ⇌ P C l_{3 (g)} + C l_{2 (g)}

2 H I_{(g)} ⟶ H_{2 (g)} + I_{2 (g)}

2 N H_{3 (g)} ⟶ N_{2 (g)} + 3 H_{2 (g)}

2 N O_{(g)} ⟶ N_{2 (g)} + O_{2 (g)}

P C l_{5 (g)} ⟶ P C l_{3 (g)} + C l_{2 (g)}

For the reaction, $P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)$ , the degree of dissociation 'x' is related to pressure 'P(x<<1)

0.4

400 K

1.0 a t m

P C l_{5} ⇌ P C l_{3} + C l_{2} (g)

400 K

1.0 a t m

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