For the reaction represented by the equation- CX4 - 2O2- CO2 - 2X2O 9-0 g of CX4 completely reacts with 1-74 g of oxygen- The approximate molar mass of X will be-

The correct option is D 80 CX_4+2O_2 → CO_2+2X_2O 1 mol #160; 2mol #160;9.0 g #160; #160; #160;1.74 g ∵ 1.74 g O_2 reacts with CX ...

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Byju's Answer

Standard XII

Chemistry

Stoichiometry

For the react...

Question

For the reaction represented by the equation,

$C X_{4} + 2 O_{2} \to C O_{2} + 2 X_{2} O$

9.0 g of $C X_{4}$ completely reacts with 1.74 g of oxygen. The approximate molar mass of X will be:

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Solution

The correct option is D 80
$C X_{4} + 2 O_{2} \to C O_{2} + 2 X_{2} O$
1 mol 2mol

9.0 g 1.74 g

$∵ 1.74 g O_{2}$ reacts with $C X_{4} = 9.0 g$

$∴ 64 g O_{2}$ will react with $C X_{4} = \frac{9.0 \times 64}{1.74} = 331$

Molecular mass of $C X_{4} = 331$

Or
$331 = 12 + 4 X$

$X = \frac{331 - 12}{4} = 79.8 \approx 80$

Hence, option D is correct.

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Similar questions

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Q. (i) Use the expressions

{C X}_{4}

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Q. Oxygen gas reacts with hydrogen to produce water. The reaction is represented by the equation:

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For the reaction represented by the equation, CX4+2O2→CO2+2X2O 9.0 g of CX4 completely reacts with 1.74 g of oxygen. The approximate molar mass of X will be:

The correct option is D 80CX4+2O2→CO2+2X2O1 mol 2mol 9.0 g 1.74 g∵1.74gO2 reacts with CX4=9.0g∴64gO2 will react with CX4=9.0×641.74=331Molecular mass of CX4=331Or 331=12+4XX=331−124=79.8≈80Hence, option D is correct.

For the reaction represented by the equation,

$C X_{4} + 2 O_{2} \to C O_{2} + 2 X_{2} O$

9.0 g of $C X_{4}$ completely reacts with 1.74 g of oxygen. The approximate molar mass of X will be: