For the reaction, $S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇋ S O_{3} (g)$
If $K_{p} = K_{c} (R T)^{x}$ where, the symbols have usual meaning, then the value of x is (assuming ideality)

-1

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- \frac{1}{2}

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\frac{1}{2}

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Solution

The correct option is B $- \frac{1}{2}$
For the given reaction, $Δ n_{g} = n_{p} - n_{g}$
Where, $n_{p}$ = number of moles of products
$n_{g}$ = number of moles of reactants
$K_{p} = K_{c} (R T)^{Δ n_{g}}$
$Δ n_{g} = - \frac{1}{2}$

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