For the reaction, $S O_{2 (g)} + \frac{1}{2} O_{2 (g)} ⇌ S O_{3 (g)}$ , if $K_{P} = K_{C} (R T)^{x}$ where the symbols have usual meaning then the value of $x$ is (assuming ideality) :

\frac{1}{2}

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1

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- 1

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- \frac{1}{2}

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Solution

The correct option is B $- \frac{1}{2}$
For reaction: $S O_{2 (g)} + \frac{1}{2} O_{2 (g)} ⇌ S O_{3 (g)}$
$Δ n_{g} = - \frac{1}{2} = x$

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