For the reaction SO 2 g - 1 2 O 2 g - SO 3 g - - H 300 -95 kJ-mole- - S 300 -95-0 kJ-K mole- Find the value of In K p for this reaction 300 K-

G= H T S #160; #160; #160; #160; = 95 ( 300×( 95 ) #160; ) #160; #160; n=1 1.5=0.5 #160; #160; #160; #160; ...

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Vant Hoff's Equation and Effect of Temperature on Equilibrium Constant

For the react...

Question

For the reaction ${S O}_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ {S O}_{3} (g); {Δ H}_{300} = - 95 k J / m o l e, {Δ S}_{300} = - 95.0 k J / K m o l e$ . Find the value of In $K_{p}$ for this reaction 300 K.

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S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ {S O}_{3} (g)

K_{c}

1.7 \times 10^{12}

300 K

300 K

2 S O_{2} (g) + O_{2} (g) ⇌ 2 {S O}_{3} (g)

{S O}_{3} (g) ⇌ S O_{2} (g) + \frac{1}{2} O_{2} (g)

S O_{2} (g) + 1 / 2 O_{2} (g) ⇌ S O_{3} (g) Δ H_{298}^{o} = 98.32 k J / m o l e, Δ S_{298}^{o} = 95.0 J / K / m o l e

K_{p}

K_{c} = 4.9 \times 10^{- 2}

{S O}_{3} (g) ⇌ {S O}_{2} (g) + \frac{1}{2} O_{2} (g)

K_{c}

2 {S O}_{2} (g) + O_{2} (g) ⇌ 2 {S O}_{3} (g)

S O_{3} (g) ⇌ S O_{2} (g) + \frac{1}{2} O_{2} (g)

K_{c} = 4.9 \times 10^{- 2}

K_{c}

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)

K_{c}

S O_{3 (g)} ⇌

+ \frac{1}{2} O_{2} (g)

4.9 \times 10^{- 2}

K_{c}

2 S O_{2 (g)} + O_{2} (g) ⇌ 2 S O_{3} (g)

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