For the reaction, the major product is formed by:

An E

1

reaction

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An E

2

reaction

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S_{N} 1

reaction

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S_{N} 2

reaction

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Solution

The correct option is B An E $2$ reaction
Since, ${C H}_{3} {C H}_{2} O$ is a moderate base, so there is no possibility
of $E_{1}$ reaction and in $E_{1 C B}$ , there takes place the carbanion
formation. Hex, there is no anion stabilising group, so $E_{1} C B$ is not possible.
E. mechanism is possible because of presence of $H$ -atom anti
to the leaving group $(B r)$ .
So, option(B) is correct.

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Similar questions

$S_{N} 1$ solvolysis of 1-(bromomethyl)cyclohex-1-ene in ethanol gives:

Q. Major product of the following

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Q. Explain

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Energy diagram of $S_{N} 1$ and $S_{N} 2$ reactions The order of hydrolysis of RX by $S N^{1}$ is $3^{\circ} > 2^{\circ} > 1^{\circ}$ RX and $S N^{2}$ path is $1^{\circ} > 2^{\circ} > 3^{\circ}$ RX.

Which of the following statements are correct for the above energy diagrams of $S_{N} 1$ and $S_{N} 2$ reactions?

Q. Difference between

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