Question

For the reaction, the major product is formed by:

• A. An E$1$ reaction
• B. An E$2$ reaction
• C. $S_{N}1$ reaction
• D. $S_{N}2$ reaction

Answer 1

The correct option is B An E$2$ reaction

Since, ${CH}_3{CH}_{2}O$ is a moderate base, so there is no possibility

of $E_1$ reaction and in $E_{1CB}$, there takes place the carbanion

formation. Hex, there is no anion stabilising group, so $E_{1}CB$ is not possible.

E. mechanism is possible because of presence of $H$ -atom anti

to the leaving group $\left(Br\right)$.

So, option(B) is correct.