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Industrial Preparation of Ammonia

For the react...

Question

For the reaction $X_{2} Y_{4 (l)} ⟶ 2 X Y_{2 (g)}$ at 300 K the values of $△ U$
and $△ S$ are $2$ and $20$ $K^{- 1}$ respectively. The value of $△ G$ for the reaction is:

- 3400

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3400

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- 2800

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2000

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Solution

The correct option is C C. $- 2800$

$△ G = △ H - T △ S △ H = △ U + △ x_{g} R T △ x_{g} = 2 - 0 = 2$

$△ H = 2000 + 2 \times 2 \times 300 = 2000 + 1200 = 3200$

$△ G = 3200 - 300 \times 20 = 3200 - 6000 = - 2800.$

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For the reaction X2Y4(l)⟶2XY2(g) at 300 K the values of △Uand △S are 2 and 20 K−1 respectively. The value of △G for the reaction is:

The correct option is C C.−2800△G=△H−T△S△H=△U+△xgRT△xg=2−0=2△H=2000+2×2×300=2000+1200=3200△G=3200−300×20=3200−6000=−2800.

For the reaction $X_{2} Y_{4 (l)} ⟶ 2 X Y_{2 (g)}$ at 300 K the values of $△ U$
and $△ S$ are $2$ and $20$ $K^{- 1}$ respectively. The value of $△ G$ for the reaction is:

The correct option is C C. $- 2800$

$△ G = △ H - T △ S △ H = △ U + △ x_{g} R T △ x_{g} = 2 - 0 = 2$

$△ H = 2000 + 2 \times 2 \times 300 = 2000 + 1200 = 3200$

$△ G = 3200 - 300 \times 20 = 3200 - 6000 = - 2800.$