For the rectangular solid in Geometry Figure $40$ below, find the following.
a)The surface area of the solid
b)The length of diagonal $A B$

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Solution

$l = 10, b = 7, h = 2$
Surface area
$= 2 (l b + b h + h l)$
$2 (10 \times 7 + 7 \times 2 + 2 \times 10) = 208$
Length of diagonal
$= \sqrt{l^{2} + b^{2} + h^{2}}$
$= \sqrt{(10)^{2} + (7^{2}) + (2)^{2}} = 3 \sqrt{17}$

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For the rectangular solid in Geometry Figure 40 below, find the following.a)The surface area of the solidb)The length of diagonal AB

l=10,b=7,h=2Surface area =2(lb+bh+hl)2(10×7+7×2+2×10)=208Length of diagonal =√l2+b2+h2=√(10)2+(72)+(2)2=3√17

For the rectangular solid in Geometry Figure $40$ below, find the following.
a)The surface area of the solid
b)The length of diagonal $A B$

$l = 10, b = 7, h = 2$
Surface area
$= 2 (l b + b h + h l)$
$2 (10 \times 7 + 7 \times 2 + 2 \times 10) = 208$
Length of diagonal
$= \sqrt{l^{2} + b^{2} + h^{2}}$
$= \sqrt{(10)^{2} + (7^{2}) + (2)^{2}} = 3 \sqrt{17}$