For the redox reaction xP 4- yHNO 3- H 3 PO 4- NO 2- H 2 OA- x -2- y -10B- x -1- y -15C- x -1- y -5D- x -1- y -20

The correct option is D x = 1, y = 20The balanced equation is P_4 + 20 HNO_3 → 4H_3PO_4 + 20 NO_2 + 4 H_2O ...

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Frankland Halide Reaction

For the redox...

Question

For the redox reaction $x P_{4} + y H N O_{3} \to H_{3} P O_{4} + N O_{2} + H_{2} O$

x = 1, y = 5

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x = 2, y = 10

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x = 1, y = 20

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x = 1, y = 15

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Solution

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Similar questions

x P_{4} + y H N O_{3} \to H_{3} P O_{4} + N O_{2} + H_{2} O

x H I + y H N O_{3} \to N O + I_{2} + H_{2} O

x H I + y H N O_{3} \to N O + I_{2} + H_{2} O

In the redox reaction

xMnO +y $P b O_{2}$ +z $H N O_{3}$ $⟶$ $H M n O_{4}$ + $P b (N O_{3})_{2}$ + $H_{2} O$

$\begin{matrix} X & 1 & 2 & 3 & 4 Y & 10 & 20 & 30 & 40 \end{matrix}$
What would be the constant that defines the value $\frac{X}{Y}$ ?

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